Question

for an aqueous solution of sodium chloride, determine the molarity of 6.63 l of a solution that contains 169.4 g of solute. report your answer to two places after the decimal point.

Explanation:

Step1: Calculate the molar mass of NaCl

The molar mass of \(Na\) is \(22.99\ g/mol\) and the molar mass of \(Cl\) is \(35.45\ g/mol\). So the molar mass of \(NaCl\), \(M = 22.99+35.45=58.44\ g/mol\)

Step2: Calculate the number of moles of \(NaCl\)

Using the formula \(n=\frac{m}{M}\), where \(m = 169.4\ g\) and \(M = 58.44\ g/mol\). Then \(n=\frac{169.4}{58.44}\approx 2.90\ mol\)

Step3: Calculate the molarity of the solution

Using the formula \(C=\frac{n}{V}\), where \(n = 2.90\ mol\) and \(V=6.63\ L\). Then \(C=\frac{2.90}{6.63}\approx0.44\ mol/L\)

Answer:

\(0.44\)