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another balancing equations sheet! balance these equations! 1) ____ alb…

Question

another balancing equations sheet!
balance these equations!

  1. __ albr₃ + k → kbr + __ al
  2. __ feo + pdf₂ → fef₂ + __ pdo
  3. __ p₄ + br₂ → __ pbr₃
  4. __ licl + br₂ → libr + __ cl₂
  5. __ pbbr₂ + hcl → hbr + __ pbcl₂
  6. __ na₃p + caf₂ → naf + __ ca₃p₂
  7. __ mn + hi → h₂ + __ mni₃
  8. __ li₃po₄ + nabr → na₃po₄ + __ libr
  9. __ caf₂ + li₂so₄ → caso₄ + __ lif
  10. __ hbr + mg(oh)₂ → mgbr₂ + __ h₂o
  11. __ agno₃ + li → lino₃ + __ ag
  12. __ si(oh)₄ + nabr → sibr₄ + __ naoh
  13. __ nacn + cuco₃ → na₂co₃ + __ cu(cn)₂

Explanation:

Step1: Balance equation 1

For \(AlBr_3+K
ightarrow KBr + Al\), balance \(Br\) first. There are \(3\) \(Br\) atoms in \(AlBr_3\), so put \(3\) in front of \(KBr\). Then balance \(K\), put \(3\) in front of \(K\). The balanced equation is \(AlBr_3 + 3K=3KBr+Al\).

Step2: Balance equation 2

For \(FeO+PdF_2
ightarrow FeF_2+PdO\), count the number of each atom. The equation is already balanced as \(FeO + PdF_2=FeF_2+PdO\).

Step3: Balance equation 3

For \(P_4+Br_2
ightarrow PBr_3\), balance \(P\) first. Put \(4\) in front of \(PBr_3\). Then balance \(Br\), put \(6\) in front of \(Br_2\). The balanced equation is \(P_4 + 6Br_2 = 4PBr_3\).

Step4: Balance equation 4

For \(LiCl+Br_2
ightarrow LiBr+Cl_2\), balance \(Cl\) and \(Br\). Put \(2\) in front of \(LiCl\) and \(2\) in front of \(LiBr\). The balanced equation is \(2LiCl+Br_2 = 2LiBr+Cl_2\).

Step5: Balance equation 5

For \(PbBr_2+HCl
ightarrow HBr+PbCl_2\), balance \(Br\) and \(Cl\). Put \(2\) in front of \(HCl\) and \(2\) in front of \(HBr\). The balanced equation is \(PbBr_2+2HCl = 2HBr+PbCl_2\).

Step6: Balance equation 7

For \(Na_3P+CaF_2
ightarrow NaF+Ca_3P_2\), balance \(Na\), \(P\) and \(Ca\). Put \(2\) in front of \(Na_3P\), \(6\) in front of \(NaF\) and \(3\) in front of \(CaF_2\). The balanced equation is \(2Na_3P+3CaF_2 = 6NaF+Ca_3P_2\).

Step7: Balance equation 8

For \(Mn+HI
ightarrow H_2+MnI_3\), balance \(I\) first. Put \(3\) in front of \(HI\) and \(\frac{3}{2}\) in front of \(H_2\). Multiply by \(2\) to get whole - number coefficients. The balanced equation is \(2Mn + 6HI=3H_2+2MnI_3\).

Step8: Balance equation 9

For \(Li_3PO_4+NaBr
ightarrow Na_3PO_4+LiBr\), balance \(Na\) and \(Li\). Put \(3\) in front of \(NaBr\) and \(3\) in front of \(LiBr\). The balanced equation is \(Li_3PO_4+3NaBr = Na_3PO_4+3LiBr\).

Step9: Balance equation 10

For \(CaF_2+Li_2SO_4
ightarrow CaSO_4+LiF\), balance \(F\). Put \(2\) in front of \(LiF\). The balanced equation is \(CaF_2+Li_2SO_4 = CaSO_4+2LiF\).

Step10: Balance equation 11

For \(HBr+Mg(OH)_2
ightarrow MgBr_2+H_2O\), balance \(Br\) and \(H\). Put \(2\) in front of \(HBr\) and \(2\) in front of \(H_2O\). The balanced equation is \(2HBr+Mg(OH)_2 = MgBr_2+2H_2O\).

Step11: Balance equation 13

For \(AgNO_3+Li
ightarrow LiNO_3+Ag\), the equation is already balanced as \(AgNO_3+Li = LiNO_3+Ag\).

Step12: Balance equation 14

For \(Si(OH)_4+NaBr
ightarrow SiBr_4+NaOH\), balance \(Br\) and \(Na\). Put \(4\) in front of \(NaBr\) and \(4\) in front of \(NaOH\). The balanced equation is \(Si(OH)_4+4NaBr = SiBr_4+4NaOH\).

Step13: Balance equation 15

For \(NaCN+CuCO_3
ightarrow Na_2CO_3+Cu(CN)_2\), balance \(Na\) and \(CN\). Put \(2\) in front of \(NaCN\). The balanced equation is \(2NaCN+CuCO_3 = Na_2CO_3+Cu(CN)_2\).

Answer:

  1. \(1\) \(AlBr_3 + 3K = 3KBr+1\) \(Al\)
  2. \(1\) \(FeO + 1\) \(PdF_2=1\) \(FeF_2+1\) \(PdO\)
  3. \(1\) \(P_4 + 6Br_2 = 4PBr_3\)
  4. \(2\) \(LiCl+1\) \(Br_2 = 2LiBr+1\) \(Cl_2\)
  5. \(1\) \(PbBr_2+2HCl = 2HBr+1\) \(PbCl_2\)
  6. \(2\) \(Na_3P+3CaF_2 = 6NaF+1\) \(Ca_3P_2\)
  7. \(2\) \(Mn + 6HI=3H_2+2\) \(MnI_3\)
  8. \(1\) \(Li_3PO_4+3NaBr = 1\) \(Na_3PO_4+3\) \(LiBr\)
  9. \(1\) \(CaF_2+1\) \(Li_2SO_4 = 1\) \(CaSO_4+2\) \(LiF\)
  10. \(2\) \(HBr+1\) \(Mg(OH)_2 = 1\) \(MgBr_2+2\) \(H_2O\)
  11. \(1\) \(AgNO_3+1\) \(Li = 1\) \(LiNO_3+1\) \(Ag\)
  12. \(1\) \(Si(OH)_4+4NaBr = 1\) \(SiBr_4+4\) \(NaOH\)
  13. \(2\) \(NaCN+1\) \(CuCO_3 = 1\) \(Na_2CO_3+1\) \(Cu(CN)_2\)