Question

aluminum and liquid bromine reaction
substance before reaction after reaction
aluminum 10.3 g 0.0 g
liquid bromine 100.0 g 8.2 g
compound 0.0 g
how many grams of bromine reacted? how many grams of compound were formed?

1. from a laboratory process designed to separate water into hydrogen and oxygen gas, a student collected 10.0 g of hydrogen and 79.4 g of oxygen. how much water was originally involved in the process?
2. a student carefully placed 15.6 g of sodium in a reactor supplied with an excess quantity of chlorine gas. when the reaction was complete, the student obtained 39.7 g of sodium chloride. calculate how many grams of chlorine gas reacted. how many grams of sodium reacted?
3. a 10.0 - g sample of magnesium reacts with oxygen to form 16.6 g of magnesium oxide. how many grams of oxygen reacted?

Explanation:

Step1: Calculate grams of bromine reacted

Initial mass of liquid bromine is 100.0 g and final mass is 8.2 g. Subtract final mass from initial mass.
$100.0 - 8.2=91.8$ g

Step2: Calculate grams of compound formed

According to the law of conservation of mass, the total mass before reaction equals total mass after reaction. Mass of aluminum before reaction is 10.3 g and mass of bromine that reacted is 91.8 g. The mass of the compound formed is the sum of the mass of aluminum that reacted and the mass of bromine that reacted.
$10.3 + 91.8 = 102.1$ g

Answer:

The grams of bromine that reacted is 91.8 g and the grams of compound formed is 102.1 g.