Question

al^{3+}
express your answer in complete form, in order of increasing orbital. for example, 1s^{2}2s^{2} would be entered as 1s^22s^2.

Explanation:

Step1: Determine the atomic number of Al

The atomic number of Al (aluminum) is 13. So, a neutral Al atom has 13 electrons.

Step2: Consider the charge of \(Al^{3 +}\)

Since \(Al^{3+}\) has a + 3 charge, it has lost 3 electrons. So, the number of electrons in \(Al^{3+}\) is \(13 - 3=10\) electrons.

Step3: Write the electron - configuration

The electron - configuration of an atom/ion with 10 electrons is based on the Aufbau principle. The order of filling orbitals (for low - energy orbitals) is \(1s<2s<2p\).
The number of electrons in \(1s\) orbital: 2
The number of electrons in \(2s\) orbital: 2
The number of electrons in \(2p\) orbital: \(10-(2 + 2)=6\)

Answer:

\(1s^22s^22p^6\) (entered as \(1s^{\wedge}22s^{\wedge}22p^{\wedge}6\))