Question

aktiv will undergo scheduled maintenance on oct 19 from 5am to 8am et. during this period, the platform may be temporarily unavailable. question 32 of 37 write a balanced chemical equation based on the following description: solid yttrium metal reacts with nitrogen gas to produce solid yttrium(iii) nitride y(s) + n₂(g) →

Explanation:

Step1: Write the unbalanced equation

The reaction is between yttrium (\(Y\)) and nitrogen (\(N_2\)) to form yttrium(III) nitride (\(YN\)). So the un - balanced equation is \(Y(s)+N_2(g)\to YN(s)\)

Step2: Balance the nitrogen atoms

There are 2 nitrogen atoms on the left - hand side (\(N_2\)) and 1 on the right - hand side (\(YN\)). To balance the nitrogen atoms, we put a coefficient of 2 in front of \(YN\). The equation becomes \(Y(s)+N_2(g)\to 2YN(s)\)

Step3: Balance the yttrium atoms

Now, there are 2 yttrium atoms on the right - hand side (\(2YN\)) and 1 on the left - hand side (\(Y\)). So we put a coefficient of 2 in front of \(Y\). The balanced equation is \(2Y(s)+N_2(g)\to 2YN(s)\)

Answer:

\(2Y(s)+N_2(g)\to 2YN(s)\)