Question

1. add coefficients to balance the equation when aqueous solutions of potassium hydroxide and cobalt(iii) nitrate are mixed..

? co(no₃)₃ + ? koh → ? co(oh)₃ + ? kno₃
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Explanation:

Step1: Balance Co atoms

There is 1 Co in \( \text{Co(NO}_3\text{)}_3 \) and 1 Co in \( \text{Co(OH)}_3 \), so Co is balanced initially. So coefficient for \( \text{Co(NO}_3\text{)}_3 \) and \( \text{Co(OH)}_3 \) can start as 1.

Step2: Balance \( \text{NO}_3^- \) ions

In \( \text{Co(NO}_3\text{)}_3 \), there are 3 \( \text{NO}_3^- \) ions. In \( \text{KNO}_3 \), each has 1 \( \text{NO}_3^- \). So to balance \( \text{NO}_3^- \), coefficient of \( \text{KNO}_3 \) should be 3.

Step3: Balance K atoms

In \( \text{KNO}_3 \), there are 3 K atoms, so coefficient of \( \text{KOH} \) should be 3 (since each \( \text{KOH} \) has 1 K).

Step4: Balance \( \text{OH}^- \) ions

In \( \text{KOH} \), there are 3 \( \text{OH}^- \) ions (from 3 KOH), and in \( \text{Co(OH)}_3 \), there are 3 \( \text{OH}^- \) ions, so \( \text{OH}^- \) is balanced.

So the balanced equation is: \( 1\text{Co(NO}_3\text{)}_3 + 3\text{KOH}
ightarrow 1\text{Co(OH)}_3 + 3\text{KNO}_3 \)

Answer:

1, 3, 1, 3 (coefficients for \( \text{Co(NO}_3\text{)}_3 \), \( \text{KOH} \), \( \text{Co(OH)}_3 \), \( \text{KNO}_3 \) respectively)