Question

a 0.75 mol gas occupies 15.0 l at 310 k. find the pressure.

Explanation:

Step1: <Ideal gas law formula>

The ideal gas law is \(PV = nRT\). We need to find \(P\), so we can rewrite the formula as \(P=\frac{nRT}{V}\).

Step2: <Substitute the values>

Given \(n = 0.75\space mol\), \(R=0.0821\space L\cdot atm/(mol\cdot K)\), \(T = 310\space K\), \(V=15.0\space L\).
Substitute these values into the formula: \(P=\frac{0.75\times0.0821\times310}{15.0}\).
First calculate the numerator: \(0.75\times0.0821\times310 = 0.75\times25.451=19.08825\).
Then divide by \(V\): \(P=\frac{19.08825}{15.0}\).

Answer:

\(P = 1.27\space atm\)