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6li(s) + n₂(g) → 2li₃n(s) part 1 of 2 what is the theoretical yield of …

Question

6li(s) + n₂(g) → 2li₃n(s)
part 1 of 2
what is the theoretical yield of li₃n in grams when 12.5 g of li is heated with 34.1 g of n₂? round your answer to 3 significant digits.
20.9 g
part: 1 / 2
part 2 of 2
if the actual yield of li₃n is 6.29 g, what is the percent yield of the reaction? round your answer to 3 significant digits.
%

Explanation:

Step1: Calculate the theoretical yield (already given as 20.9 g)

Given in the problem statement.

Step2: Calculate the percent yield

The formula for percent yield is \(\text{Percent Yield}=\frac{\text{Actual Yield}}{\text{Theoretical Yield}}\times100\%\)
Substitute Actual Yield = \(6.29\) g and Theoretical Yield = \(20.9\) g
\(\text{Percent Yield}=\frac{6.29}{20.9}\times 100\%\)
\(\text{Percent Yield}=0.301\times100\% = 30.1\%\)

Answer:

\(30.1\%\)