Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

8.6e: investigate how mass is conserved in chemical reactions and relat…

Question

8.6e: investigate how mass is conserved in chemical reactions and relate conservation of mass to the rearrangement of atoms using chemical equations, including photosynthesis.
a chemical equation for the reaction between calcium carbonate, caco₃, and hydrochloric acid, 2hcl, is shown. the masses of some of the reactants and products are given in grams.
caco₃ + 2hcl → cacl₂ + h₂o + co₂
—— 98 g 96 g 40 g 36 g
how many grams of calcium carbonate were used in the reaction?
a. 100 g
b. 36 g
c. 74 g
d. 62 g
determine if the following chemical equations are balanced or unbalanced.
ch₄ + 2o₂ → co₂ + 2h₂o
balanced or unbalanced?
h₃po₄ + koh → k₃po₄ + 3h₂o
balanced or unbalanced?
which statement best describes evidence that a chemical reaction occurs as a cake bakes?
a. the water in the cake batter is used to keep the cake moist as it bakes.
b. the cake takes the shape of the container in which it is baked.
c. the cake rises as gas bubbles form in the baking cake.
d. the water in the cake batter evaporates.
which of the following best illustrates the law of conservation of mass?
a. 3agno₃ + 2cu → cu(no₃)₂ + 2ag
b. 2agno₃ + cu → cu(no₃)₂ + 2ag
c. agno₃ + 2cu → 2cu(no₃)₂ + 2ag
8.10a: describe how energy from the sun, hydrosphere, and atmosphere interact and influence weather and climate
how does the interaction between the hydrosphere and the atmosphere contribute to the formation of a weather front?
a. water vapor from the ocean condenses directly into precipitation without affecting atmospheric conditions
b. the hydrosphere and atmosphere interact to keep the air temperature constant, preventing the formation of weather fronts
c. cool air from the atmosphere directly influences ocean currents without any impact on weather patterns or fronts.
d. evaporation from the ocean increases atmospheric humidity, which, when interacting with cooler air masses, can lead to cloud formation and precipitation along a weather front
which of the following best describes how the interaction of energy from the sun, the hydrosphere, and the atmosphere influences weather and climate?
a. the sun’s energy causes evaporation from the oceans, which increases atmospheric pressure and leads to clear, stable weather
b. solar energy heats the earth’s surface, causing differences in air pressure that drive wind patterns and influence weather systems, while the hydrosphere and atmosphere interact to distribute heat and moisture globally.
c. the sun’s energy is absorbed equally by all parts of the earth, leading to uniform weather conditions and a consistent climate.
d. energy from the sun causes direct warming of the atmosphere, while the hydrosphere has no significant impact on weather and climate

Explanation:

First Sub - Question (Mass Conservation in Chemical Reactions)
Step 1: Recall the Law of Conservation of Mass

The law of conservation of mass states that in a chemical reaction, the total mass of reactants is equal to the total mass of products. The formula for this is \(m_{reactants}=m_{products}\), where \(m_{reactants}\) is the sum of the masses of all reactants and \(m_{products}\) is the sum of the masses of all products.

Step 2: Calculate the total mass of products

The products are \(CaCl_2\) (96 g), \(H_2O\) (40 g), and \(CO_2\) (36 g). So, \(m_{products}=96 + 40+36=172\) g.

Step 3: Calculate the mass of \(CaCO_3\)

We know the mass of \(HCl\) is 98 g. Let the mass of \(CaCO_3\) be \(x\). Then, \(x + 98=m_{products}=172\). Solving for \(x\), we get \(x = 172 - 98 = 74\) g.

Step 1: Count the number of each atom on the reactant side
  • For \(C\): In \(CH_4\), there is 1 \(C\) atom.
  • For \(H\): In \(CH_4\), there are \(4\) \(H\) atoms.
  • For \(O\): In \(2O_2\), there are \(2\times2 = 4\) \(O\) atoms.
Step 2: Count the number of each atom on the product side
  • For \(C\): In \(CO_2\), there is 1 \(C\) atom.
  • For \(H\): In \(2H_2O\), there are \(2\times2=4\) \(H\) atoms.
  • For \(O\): In \(CO_2\) (2 \(O\) atoms) and \(2H_2O\) (2\times1 = 2 \(O\) atoms), total \(O\) atoms are \(2 + 2=4\) \(O\) atoms.

Since the number of each type of atom is the same on both sides, the equation is balanced.

Step 1: Count the number of each atom on the reactant side
  • For \(P\): In \(H_3PO_4\), there is 1 \(P\) atom.
  • For \(H\): In \(H_3PO_4\) (3 \(H\) atoms) and \(KOH\) (let the number of \(KOH\) be \(x\), so \(x\) \(H\) atoms from \(KOH\)).
  • For \(O\): In \(H_3PO_4\) (4 \(O\) atoms) and \(KOH\) ( \(x\) \(O\) atoms from \(KOH\)).
  • For \(K\): In \(KOH\), there is \(x\) \(K\) atoms.
Step 2: Count the number of each atom on the product side
  • For \(P\): In \(K_3PO_4\), there is 1 \(P\) atom.
  • For \(H\): In \(3H_2O\), there are \(3\times2 = 6\) \(H\) atoms.
  • For \(O\): In \(K_3PO_4\) (4 \(O\) atoms) and \(3H_2O\) (3 \(O\) atoms), total \(O\) atoms are \(4 + 3=7\) \(O\) atoms.
  • For \(K\): In \(K_3PO_4\), there are 3 \(K\) atoms.

Now, let's balance the \(K\) first. Since there are 3 \(K\) atoms in the product (\(K_3PO_4\)), the number of \(KOH\) (which provides \(K\)) should be 3. So \(x = 3\).

Now check \(H\): Reactant \(H\): \(3\) (from \(H_3PO_4\))+\(3\) (from 3 \(KOH\))=\(6\), which matches the product \(H\) (6 from \(3H_2O\)).

Check \(O\): Reactant \(O\): \(4\) (from \(H_3PO_4\))+\(3\) (from 3 \(KOH\))=\(7\), which matches the product \(O\) (4 + 3 = 7).

So the equation is balanced.

Answer:

\(\boldsymbol{74}\) g (Option C)

Second Sub - Question (Balancing \(CH_4 + 2O_2

ightarrow CO_2+2H_2O\))