Question

4.60×10²³ lead atoms
m =
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Explanation:

Step1: Recall Avogadro's number and molar mass of lead

Avogadro's number is \( 6.022\times10^{23} \) atoms/mol. The molar mass of lead (Pb) is approximately \( 207.2 \) g/mol.

Step2: Calculate moles of lead atoms

Moles (\( n \)) = number of atoms / Avogadro's number. So \( n=\frac{4.60\times 10^{23}}{6.022\times 10^{23}\text{ atoms/mol}} \approx 0.764 \) mol.

Step3: Calculate mass of lead

Mass (\( m \)) = moles × molar mass. So \( m = 0.764\text{ mol} \times 207.2\text{ g/mol} \approx 158 \) g.

Answer:

\( 158 \) (or more precise value around 158 depending on calculation precision)