Question

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1. a 75.00 g sample of a substance is analyzed and found to consist of 32.73 g phosphorus and 42.27 g oxygen. calculate the percent composition of this substance.

Explanation:

Step1: Calculate the percent composition of phosphorus

The formula for percent composition is $\frac{\text{mass of component}}{\text{mass of sample}}\times100\%$.
For phosphorus: $\frac{32.73\ \text{g}}{75.00\ \text{g}}\times100\%$
$$=\frac{3273}{75}\%$$
$$ = 43.64\%$$

Step2: Calculate the percent composition of oxygen

For oxygen: $\frac{42.27\ \text{g}}{75.00\ \text{g}}\times100\%$
$$=\frac{4227}{75}\%$$
$$=56.36\%$$

Answer:

The percent composition of phosphorus is $43.64\%$ and the percent composition of oxygen is $56.36\%$.