Question

1. what is the mass percent of carbon in glucose, c₆h₁₂o₆? 40.00% c 25.00% c 41.40% c 72.07% c clear all

Explanation:

Step1: Calculate molar mass of glucose

Molar mass of \( C_6H_{12}O_6 \) = (6×atomic mass of C) + (12×atomic mass of H) + (6×atomic mass of O)
Atomic masses: C = 12.01 g/mol, H = 1.008 g/mol, O = 16.00 g/mol
So, molar mass = \( 6\times12.01 + 12\times1.008 + 6\times16.00 \)
= \( 72.06 + 12.096 + 96.00 \)
= \( 180.156 \) g/mol

Step2: Calculate total mass of C in glucose

Mass of C in \( C_6H_{12}O_6 \) = 6×12.01 = 72.06 g/mol

Step3: Calculate mass percent of C

Mass percent of C = \( \frac{\text{Mass of C}}{\text{Molar mass of glucose}} \times 100\% \)
= \( \frac{72.06}{180.156} \times 100\% \)
≈ 40.00%

Answer:

40.00% C (the option with "40.00% C")