Question

2al + 3sn²⁺ → 2al³⁺ + 3sn
in the voltaic cell above, which letter represents the cathode half - cell?

Explanation:

In a voltaic cell, the cathode is where reduction occurs. The given reaction is \(2\text{Al} + 3\text{Sn}^{2+}
ightarrow 2\text{Al}^{3+} + 3\text{Sn}\). Here, \(\text{Sn}^{2+}\) gains electrons (is reduced) to form \(\text{Sn}\). The half - cell with the \(\text{Sn}\) electrode (beaker A) is where the reduction of \(\text{Sn}^{2+}\) takes place, so it is the cathode half - cell.

Answer:

A (the beaker with the Sn electrode)