Question

2ag(s) + i₂(s) → 2agi(s)
what is the correct ratio of moles of the substances in the chemical equation?
2 moles ag : 2 moles i : 2 moles agi
2 atoms ag : 1 molecule i₂ : 2 formula units agi
1 mole ag : 1 mole i₂ : 1 mole agi
2 moles ag : 1 mole i₂ : 2 moles agi

Explanation:

Step1: Analyze the coefficients in the chemical equation

In the given equation \(2Ag(s)+I_2(s)\to2AgI(s)\), the coefficients represent the number of moles of each substance.
For \(Ag\), the coefficient is \(2\), for \(I_2\) it is \(1\), and for \(AgI\) it is \(2\).

Step2: Check each option

• Option 1: \(2\) moles \(Ag:2\) moles \(I:2\) moles \(AgI\) is incorrect because in the reactant side, it is \(I_2\) (not \(I\) as a single atom in terms of moles for the given reaction context).
• Option 2: \(2\) atoms \(Ag:1\) molecule \(I_2:2\) formula units \(AgI\) is about the number of particles (atoms, molecules, formula units) not moles as the question asks for moles ratio.
• Option 3: \(1\) mole \(Ag:1\) mole \(I_2:1\) mole \(AgI\) does not match the coefficients \(2,1,2\) in the balanced equation.
• Option 4: \(2\) moles \(Ag:1\) mole \(I_2:2\) moles \(AgI\) matches the coefficients in the balanced chemical equation \(2Ag(s)+I_2(s)\to2AgI(s)\)

Answer:

\(2\) moles \(Ag:1\) mole \(I_2:2\) moles \(AgI\) (the fourth option)