Question

1. crcl₃ =
2. f₂o₃ =
3. co =
4. sio₂ =
5. nahco₃ =
6. cu(no₃)₂ =

Explanation:

• For \(CrCl_{3}\): The compound consists of chromium (\(Cr\)) and chlorine (\(Cl\)). Using the naming rules for ionic compounds (metal + non - metal), it is named chromium(III) chloride (since chromium has a + 3 oxidation state to balance the - 1 charges from three \(Cl^{-}\) ions).
• For \(F_{2}O_{3}\): This is incorrect as fluorine (\(F\)) typically forms \(F^{-}\) ions. If it were \(Fe_{2}O_{3}\) (assuming a typo), it is iron(III) oxide (iron has a + 3 oxidation state to balance the - 2 charges from three \(O^{2 -}\) ions).
• For \(CO\): It is a covalent compound. Using the prefix - based naming for covalent compounds (two non - metals), it is carbon monoxide.
• For \(SiO_{2}\): It is a covalent compound. Using the prefix - based naming, it is silicon dioxide.
• For \(NaHCO_{3}\): It contains sodium (\(Na^{+}\)), hydrogen (\(H^{+}\)), and the bicarbonate (\(HCO_{3}^{-}\)) polyatomic ion. So it is named sodium bicarbonate.
• For \(Cu(NO_{3})_{2}\): It has copper (\(Cu\)) and the nitrate (\(NO_{3}^{-}\)) polyatomic ion. Copper has a + 2 oxidation state (to balance two \(-1\) charges from \(NO_{3}^{-}\)), so it is copper(II) nitrate.

Answer:

1. Chromium(III) chloride
2. (Assuming \(Fe_{2}O_{3}\)) Iron(III) oxide
3. Carbon monoxide
4. Silicon dioxide
5. Sodium bicarbonate
6. Copper(II) nitrate