Question

1. _sio₂ + _hf → _sif₄ + _h₂o
2. _kclo₃ → _kcl + ___o₂
3. _kclo₃ → _kclo₄ + ___kcl
4. _p₄o₁₀ + _h₂o → ___h₃po₄
5. _sb + _o₂ → ___sb₄o₆
6. _c₃h₈ + _o₂ → _co₂ + _h₂o
7. _fe₂o₃ + _co → _fe + _co₂
8. _pcl₅ + _h₂o → _hcl + _h₃po₄

Explanation:

Step1: Balance the first equation

For \(SiO_{2}+HF
ightarrow SiF_{4}+H_{2}O\), balance \(F\) and \(H\) atoms.
\(SiO_{2}+4HF = SiF_{4}+2H_{2}O\)

Step2: Balance the second equation

For \(KClO_{3}
ightarrow KCl + O_{2}\), balance \(O\) atoms.
\(2KClO_{3}=2KCl + 3O_{2}\)

Step3: Balance the third equation

For \(KClO_{3}
ightarrow KClO_{4}+KCl\), balance \(Cl\) and \(O\) atoms.
\(4KClO_{3}=3KClO_{4}+KCl\)

Step4: Balance the fourth equation

For \(P_{4}O_{10}+H_{2}O
ightarrow H_{3}PO_{4}\), balance \(P\) and \(H\) atoms.
\(P_{4}O_{10}+6H_{2}O = 4H_{3}PO_{4}\)

Step5: Balance the fifth equation

For \(Sb+O_{2}
ightarrow Sb_{4}O_{6}\), balance \(Sb\) and \(O\) atoms.
\(4Sb + 3O_{2}=Sb_{4}O_{6}\)

Step6: Balance the sixth equation

For \(C_{3}H_{8}+O_{2}
ightarrow CO_{2}+H_{2}O\), balance \(C\), \(H\) and \(O\) atoms.
\(C_{3}H_{8}+5O_{2}=3CO_{2}+4H_{2}O\)

Step7: Balance the seventh equation

For \(Fe_{2}O_{3}+CO
ightarrow Fe + CO_{2}\), balance \(Fe\) and \(O\) atoms.
\(Fe_{2}O_{3}+3CO = 2Fe+3CO_{2}\)

Step8: Balance the eighth equation

For \(PCl_{5}+H_{2}O
ightarrow HCl + H_{3}PO_{4}\), balance \(P\), \(Cl\) and \(H\) atoms.
\(PCl_{5}+4H_{2}O = 5HCl + H_{3}PO_{4}\)

Answer:

1. \(1SiO_{2}+4HF = 1SiF_{4}+2H_{2}O\)
2. \(2KClO_{3}=2KCl + 3O_{2}\)
3. \(4KClO_{3}=3KClO_{4}+KCl\)
4. \(1P_{4}O_{10}+6H_{2}O = 4H_{3}PO_{4}\)
5. \(4Sb + 3O_{2}=1Sb_{4}O_{6}\)
6. \(1C_{3}H_{8}+5O_{2}=3CO_{2}+4H_{2}O\)
7. \(1Fe_{2}O_{3}+3CO = 2Fe+3CO_{2}\)
8. \(1PCl_{5}+4H_{2}O = 5HCl + 1H_{3}PO_{4}\)