Question

1. what is the name of cobr2 (0.5 points) *

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1. what is the name of cu3n2 (0.5 points) *

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1. what is the name of sns2 (0.5 points) *

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1. what is the name of fen (0.5 points) *

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Explanation:

For naming ionic compounds with transition metals (which can have multiple oxidation states), we first identify the metal and the non - metal. The non - metal part is named as an anion (e.g., bromide for \(Br^-\), nitride for \(N^{3 -}\), sulfide for \(S^{2 -}\)). Then, we calculate the oxidation state of the metal using the charge of the anion and the sub - scripts in the formula.

1. For \(CoBr_2\):

• The bromide ion (\(Br^-\)) has a charge of \(- 1\). Let the oxidation state of \(Co\) be \(x\). Using the formula \(x+2\times(-1)=0\) (since the compound is neutral), we get \(x = + 2\). So the name is cobalt (II) bromide.

1. For \(Cu_3N_2\):

• The nitride ion (\(N^{3 -}\)) has a charge of \(-3\). Let the oxidation state of \(Cu\) be \(y\). Using \(3y+2\times(-3)=0\), we solve \(3y=6\), so \(y = + 2\). The name is copper (II) nitride.

1. For \(SnS_2\):

• The sulfide ion (\(S^{2 -}\)) has a charge of \(-2\). Let the oxidation state of \(Sn\) be \(z\). Using \(z + 2\times(-2)=0\), we get \(z=+4\). The name is tin (IV) sulfide.

1. For \(FeN\):

• The nitride ion (\(N^{3 -}\)) has a charge of \(-3\). Let the oxidation state of \(Fe\) be \(w\). Using \(w+(-3)=0\), we get \(w = + 3\). The name is iron (III) nitride.

Answer:

1. Cobalt (II) bromide
2. Copper (II) nitride
3. Tin (IV) sulfide
4. Iron (III) nitride