Question

1. what is the formula and specific charge on the silicite ion, if silicate is $sio_{3}^{2 - }$?

Explanation:

Step1: Identify ion naming pattern

Silicate is $\text{SiO}_3^{2-}$ (suffix "-ate"). Silicite uses "-ite", meaning one fewer oxygen atom.

Step2: Determine silicite formula

Remove one O from $\text{SiO}_3^{2-}$ → $\text{SiO}_2^{2-}$.

Step3: Confirm charge consistency

Charge remains -2 (only oxygen count changes).

Answer:

$\text{SiO}_2^{2-}$