Question

write the coordinates of the vertices after a translation 6 units left and 3 units down.

Explanation:

Step1: Determine the original coordinates

The original coordinates are \( J(3,0) \), \( K(3,7) \), \( L(9,1) \).

Step2: Apply the translation rule

The translation rule is \( (x,y)\to(x - 6,y-3) \).
For point \( J \):
\( x=3,y = 0 \)
\( x'=3-6=-3,y'=0 - 3=-3 \)
For point \( K \):
\( x = 3,y=7 \)
\( x'=3-6=-3,y'=7-3 = 4 \)
For point \( L \):
\( x=9,y = 1 \)
\( x'=9-6=3,y'=1-3=-2 \)

Answer:

\( J'(-3,-3) \), \( K'(-3,4) \), \( L'(3,-2) \)