Question

write the coordinates of the vertices after a translation 1 unit right and 6 units down.
k ( , )
l ( , )
m ( , )
n ( , )

Explanation:

Step1: Recall the translation rule

For a translation \(1\) unit right and \(6\) units down, the rule is \((x,y)\to(x + 1,y-6)\).

Step2: Find the coordinates of \(K\)

The original coordinates of \(K\) are \((-3,-3)\).
Using the rule: \(x=-3+1=-2\), \(y=-3 - 6=-9\). So \(K'(-2,-9)\).

Step3: Find the coordinates of \(L\)

The original coordinates of \(L\) are \((7,-3)\).
Using the rule: \(x = 7+1=8\), \(y=-3-6=-9\). So \(L'(8,-9)\).

Step4: Find the coordinates of \(M\)

The original coordinates of \(M\) are \((8,4)\).
Using the rule: \(x=8 + 1=9\), \(y=4-6=-2\). So \(M'(9,-2)\).

Step5: Find the coordinates of \(N\)

The original coordinates of \(N\) are \((-1,4)\).
Using the rule: \(x=-1+1=0\), \(y=4-6=-2\). So \(N'(0,-2)\).

Answer:

\(K'(-2,-9)\), \(L'(8,-9)\), \(M'(9,-2)\), \(N'(0,-2)\)