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QUESTION IMAGE

which two triangles are congruent by the sss theorem? complete the cong…

Question

which two triangles are congruent by the sss theorem? complete the congruence statement.
(image of three triangles: △dec, △ust, △ijh with congruency marks)
△□ ≅ △

Explanation:

Step1: Recall SSS Congruence

SSS (Side - Side - Side) congruence theorem states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

Step2: Analyze the Markings

  • For $\triangle DEC$ (wait, actually the first triangle is $\triangle DEC$? Wait, no, the first triangle has vertices $D$, $E$, $C$. The markings: $DE$ has three marks, $DC$ has two marks, $EC$ has one mark.
  • The second triangle is $\triangle UTS$: $UT$ has three marks, $US$? Wait, no, $UT$ has three marks, $TS$ has one mark, $US$ has three marks? Wait, no, looking at the second triangle: $UT$ (three marks), $TS$ (one mark), $US$ (three marks)? Wait, no, the third triangle is $\triangle IJH$: $IJ$ has two marks, $JH$ has one mark, $IH$ has three marks.

Wait, let's re - examine:

  • $\triangle DEC$: $DE$ (three tick marks), $DC$ (two tick marks), $EC$ (one tick mark).
  • $\triangle IJH$: $IJ$ (two tick marks), $JH$ (one tick mark), $IH$ (three tick marks).
  • $\triangle UTS$: $UT$ (three tick marks), $TS$ (one tick mark), $US$ (three tick marks)? No, wait, $UT$ (three), $US$ (three), $TS$ (one). Wait, no, the first triangle: $DE$ (three), $DC$ (two), $EC$ (one). The third triangle: $IJ$ (two), $JH$ (one), $IH$ (three). The second triangle: $UT$ (three), $US$ (one), $TS$ (three). Wait, no, maybe I mislabeled. Wait, the first triangle: vertices $D$, $E$, $C$. Sides: $DE$ (three ticks), $DC$ (two ticks), $EC$ (one tick). The third triangle: vertices $I$, $J$, $H$. Sides: $IJ$ (two ticks), $JH$ (one tick), $IH$ (three ticks). The second triangle: vertices $U$, $T$, $S$. Sides: $UT$ (three ticks), $TS$ (one tick), $US$ (three ticks). Wait, no, the correct match: $\triangle DEC$ and $\triangle IJH$? Wait, no, wait $\triangle DEC$: $DE$ (three) - corresponds to $IH$ (three) in $\triangle IJH$? No, wait, let's check the number of tick marks:
  • Three - tick sides: $DE$ (in $\triangle DEC$), $UT$ (in $\triangle UTS$), $IH$ (in $\triangle IJH$).
  • Two - tick sides: $DC$ (in $\triangle DEC$), $IJ$ (in $\triangle IJH$).
  • One - tick sides: $EC$ (in $\triangle DEC$), $JH$ (in $\triangle IJH$), $TS$ (in $\triangle UTS$).

Wait, $\triangle DEC$: sides with 3, 2, 1 ticks. $\triangle IJH$: sides with 3 (IH), 2 (IJ), 1 (JH) ticks. So by SSS, $\triangle DEC\cong\triangle IJH$? Wait, no, wait the first triangle is $\triangle DEC$? Wait, no, the first triangle is $\triangle D E C$ ( $D$, $E$, $C$), the third is $\triangle I J H$ ( $I$, $J$, $H$). Wait, or maybe the first triangle is $\triangle EDC$ and the third is $\triangle JIH$? Wait, let's do the correspondence:

  • Side with 3 ticks: $DE$ (in $\triangle EDC$) and $IH$ (in $\triangle IJH$)
  • Side with 2 ticks: $DC$ (in $\triangle EDC$) and $IJ$ (in $\triangle IJH$)
  • Side with 1 tick: $EC$ (in $\triangle EDC$) and $JH$ (in $\triangle IJH$)

So the congruence is $\triangle EDC\cong\triangle IJH$? Wait, no, maybe the first triangle is $\triangle DEC$ and the third is $\triangle IJH$. Alternatively, maybe the first triangle is $\triangle DCE$ and the third is $\triangle IHJ$. Wait, perhaps the correct pair is $\triangle DEC$ and $\triangle IJH$. Wait, but let's check again.

Wait, the first triangle: $D$, $E$, $C$. Sides: $DE$ (three), $DC$ (two), $EC$ (one). The third triangle: $I$, $J$, $H$. Sides: $IH$ (three), $IJ$ (two), $JH$ (one). So by SSS, $\triangle DEC\cong\triangle IJH$ (or $\triangle EDC\cong\triangle JIH$ depending on vertex order). But maybe the first triangle is $\triangle DCE$ and the third is $\triangle IHJ$. Wait, perhaps the intended answer is $\triangle…

Answer:

$\triangle DEC\cong\triangle IJH$ (or $\triangle EDC\cong\triangle JIH$ depending on the order of vertices, but the most appropriate is $\triangle DEC\cong\triangle IJH$)