Question

which statements are true regarding the diagram? check all that apply
cb is contained on line n
ce is contained on line m
ray bc is the same as ray cb
ray ad is the same as ray ac
∠ead is created from ae and da
∠ecb is created from ce and cb

Explanation:

Step1: Analyze line - segment and ray relations

• For $\overline{CB}$: Looking at the diagram, line - segment $\overline{CB}$ lies on line $m$.
• For $\overrightarrow{CE}$: The ray $\overrightarrow{CE}$ is also on line $m$.
• For ray $BC$ and $CB$: Ray $BC$ starts at $B$ and goes through $C$, while ray $CB$ starts at $C$ and goes through $B$. So, ray $BC

eq$ ray $CB$.

• For ray $AD$ and $AC$: Ray $AD$ starts at $A$ and goes through $D$, ray $AC$ starts at $A$ and goes through $C$. Since $D$ and $C$ are different points, ray $AD

eq$ ray $AC$.

• For $\angle EAD$: $\angle EAD$ is created from $\overrightarrow{AE}$ and $\overrightarrow{AD}$, not $\overrightarrow{AE}$ and $\overrightarrow{DA}$.
• For $\angle ECB$: By the definition of an angle formed by two rays with a common vertex, $\angle ECB$ is formed by $\overrightarrow{CE}$ (with vertex $C$) and $\overrightarrow{CB}$ (with vertex $C$).

Answer:

$\overline{CB}$ is contained on line $m$, $\overrightarrow{CE}$ is contained on line $m$, $\angle ECB$ is created from $\overrightarrow{CE}$ and $\overrightarrow{CB}$