Question

which statement is true?
△abc is similar to △cde.
△abc is not similar to △cde.

Explanation:

Step1: Calculate the third angle of $\triangle ABC$

In $\triangle ABC$, using the angle - sum property of a triangle ($\angle A+\angle B+\angle ACB = 180^{\circ}$). Given $\angle A = 62^{\circ}$ and $\angle B=41^{\circ}$, then $\angle ACB=180^{\circ}-(62^{\circ}+41^{\circ}) = 77^{\circ}$.

Step2: Calculate the third angle of $\triangle CDE$

In $\triangle CDE$, using the angle - sum property of a triangle ($\angle D+\angle E+\angle DCE = 180^{\circ}$). Let's assume the angles. But since we know the similarity condition (AA - Angle - Angle). For two triangles to be similar, their corresponding angles must be equal.
If we check the angles:
In $\triangle ABC$, angles are $62^{\circ},41^{\circ},77^{\circ}$
In $\triangle CDE$, if we assume the angles based on the figure (side - angle relationships). Since the side - angle - side (SAS) or AA similarity is not met.
We know that for similar triangles, the ratios of corresponding sides are equal and corresponding angles are equal.
Since the angles of $\triangle ABC$ ($62^{\circ},41^{\circ},77^{\circ}$) and $\triangle CDE$ (if we assume from the side - marking (equal sides marked) and angle - values) do not match.

Answer:

$\triangle ABC$ is not similar to $\triangle CDE$