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Question
which rule explains why these triangles are similar? sss sas aa none of the above; the triangles cannot be proven similar
Step1: Calculate the ratios of corresponding sides
For \(\triangle TSU\) and \(\triangle JHI\):
- \(\frac{TS}{JH}=\frac{32}{72}=\frac{4}{9}\)
- \(\frac{SU}{HI}=\frac{40}{48}=\frac{5}{6}\)
- \(\frac{UT}{IJ}=\frac{48}{60}=\frac{4}{5}\)
Since \(\frac{32}{72}
eq\frac{40}{48}
eq\frac{48}{60}\), the SSS (Side - Side - Side) similarity rule (which requires \(\frac{a}{a'}=\frac{b}{b'}=\frac{c}{c'}\) for corresponding sides \(a,a'\), \(b,b'\), \(c,c'\) of two triangles) does not apply.
There is no information about included angles to check the SAS (Side - Angle - Side) similarity rule (which requires \(\frac{a}{a'}=\frac{b}{b'}\) and the included angles to be equal). And no information about two pairs of equal angles to check the AA (Angle - Angle) similarity rule.
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none of the above; the triangles cannot be proven similar