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Question
which polygon has an interior angle sum of 900°?
Step1: Recall the formula for the sum of interior angles
The formula for the sum of interior angles of a polygon is \(S=(n - 2)\times180^{\circ}\), where \(n\) is the number of sides of the polygon.
Step2: Substitute \(S = 900^{\circ}\) into the formula
We have \(900=(n - 2)\times180\).
Step3: Solve for \(n\)
Divide both sides of the equation by \(180\): \(\frac{900}{180}=n - 2\).
Since \(\frac{900}{180}=5\), then \(5=n - 2\).
Add \(2\) to both sides: \(n=5 + 2=7\).
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