Question

which of the following equations could be used to find the area of the triangle? answer area = 1/2(43)(53)sin(51) area = 1/2(45)(53)sin(51) area = 1/2(45)(43)sin(55) area = 1/2(53)(43)sin(74)

Explanation:

Step1: Recall area formula for triangle

The area of a triangle with two - side lengths $a$ and $b$ and the included - angle $\theta$ is given by $A=\frac{1}{2}ab\sin\theta$.

Step2: Identify sides and included angle

We have side lengths $a = 45$, $b = 53$, and the included angle $\theta=51^{\circ}$.

Answer:

Area $=\frac{1}{2}(45)(53)\sin(51)$