Question

which figure has a greater area?
15.9 cm
16.3 cm
15.8 cm
16 cm
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Explanation:

Step1: Calculate area of rectangle

The first figure is a rectangle (or square-like, but with length 16.3 cm and width 15.9 cm). The area of a rectangle is given by \( A = l \times w \). So, \( A_{rectangle} = 16.3 \times 15.9 \). Calculating that: \( 16.3 \times 15.9 = 16.3 \times (16 - 0.1) = 16.3 \times 16 - 16.3 \times 0.1 = 260.8 - 1.63 = 259.17 \) \( cm^2 \).

Step2: Calculate area of parallelogram

The second figure is a parallelogram with base 16 cm and height 15.8 cm. The area of a parallelogram is \( A = base \times height \). So, \( A_{parallelogram} = 16 \times 15.8 = 252.8 \) \( cm^2 \).

Step3: Compare the areas

Now, compare 259.17 and 252.8. Since 259.17 > 252.8, the rectangle (first figure) has a greater area.

Answer:

The rectangle (the green figure with length 16.3 cm and width 15.9 cm) has a greater area.