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Question
when lines intersect, they form congruent angles and supplementary angles. the measure of ∠5 is 110°. find the remaining angle measures. m∠6 =?° m∠7 =?° m∠8 =?°
Step1: Find \(m\angle6\)
Since \(\angle5\) and \(\angle6\) are supplementary (they form a linear pair), we use the formula \(m\angle5 + m\angle6=180^{\circ}\).
Given \(m\angle5 = 110^{\circ}\), then \(m\angle6=180^{\circ}- 110^{\circ}=70^{\circ}\).
Step2: Find \(m\angle7\)
\(\angle5\) and \(\angle7\) are vertical angles. Vertical angles are congruent. So \(m\angle7=m\angle5 = 110^{\circ}\).
Step3: Find \(m\angle8\)
\(\angle6\) and \(\angle8\) are vertical angles. Vertical angles are congruent. So \(m\angle8=m\angle6 = 70^{\circ}\).
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\(m\angle6 = 70^{\circ}\), \(m\angle7 = 110^{\circ}\), \(m\angle8 = 70^{\circ}\)