Question

1. a wheel chair ramp is 5 m long and reaches to a height of 0.6 m.

a. draw a diagram of the ramp with dimensions.
b. determine the angle where the ramp touches the ground. round to one decimal place.
we know
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Explanation:

Step1: Identify the trigonometric ratio

We have a right - triangle where the hypotenuse \(c = 5m\) (length of the ramp) and the opposite side \(a=0.6m\) (height of the ramp). We use the sine ratio \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\). So, \(\sin\theta=\frac{0.6}{5}\).

Step2: Calculate the value of \(\sin\theta\)

\(\sin\theta=\frac{0.6}{5}=0.12\).

Step3: Find the angle \(\theta\)

To find \(\theta\), we use the inverse sine function \(\theta=\sin^{- 1}(0.12)\). Using a calculator, \(\theta\approx6.9^{\circ}\)

Answer:

The angle where the ramp touches the ground is approximately \(6.9^{\circ}\)