Question

what is the volume, in cubic inches, of a cylinder with a height of 4 inches and a base radius of 8 inches, to the nearest tenths place? answer attempt 1 out of 2 v =

Explanation:

Step1: Recall the formula for the volume of a cylinder

The formula for the volume \( V \) of a cylinder is \( V=\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height of the cylinder.

Step2: Substitute the given values into the formula

We are given that \( r = 8 \) inches and \( h=4 \) inches. Substituting these values into the formula, we get \( V=\pi\times(8)^{2}\times4 \).
First, calculate \( 8^{2}=64 \). Then, multiply \( 64\times4 = 256 \). So, \( V = 256\pi \).

Step3: Calculate the numerical value and round to the nearest tenths place

Using the approximation \( \pi\approx3.14159 \), we have \( V\approx256\times3.14159 \).
\( 256\times3.14159 = 804.24704 \). Rounding this to the nearest tenths place (one decimal place), we look at the hundredths digit, which is 4. Since \( 4<5 \), we round down. So, \( V\approx804.2 \).

Answer:

\( 804.2 \)