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Question
what is the volume, in cubic feet, of a cylinder with a height of 8 feet and a base radius of 5 feet, to the nearest tenths place? show examples
Step1: Recall the formula for the volume of a cylinder
The volume \( V \) of a cylinder is given by the formula \( V=\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height of the cylinder.
Step2: Substitute the given values into the formula
We are given that \( r = 5 \) feet and \( h=8 \) feet. Substituting these values into the formula, we get \( V=\pi\times(5)^{2}\times8 \).
First, calculate \( 5^{2}=25 \). Then, multiply \( 25\times8 = 200 \). So, \( V = 200\pi \).
Step3: Calculate the numerical value
Using the approximation \( \pi\approx3.14159 \), we have \( V\approx200\times3.14159=628.318 \).
Step4: Round to the nearest tenths place
Rounding \( 628.318 \) to the nearest tenths place, we look at the hundredths digit, which is 1. Since \( 1<5 \), we round down. So, \( V\approx628.3 \).
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\( 628.3 \)