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what trig function are you using to solve this problem. cosine sine tan…

Question

what trig function are you using to solve this problem. cosine sine tangent secant

Explanation:

Brief Explanations

Recall the definitions of trigonometric functions. In a right - triangle, \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\), \(\cos\theta=\frac{\text{adjacent}}{\text{hypotenuse}}\), \(\tan\theta=\frac{\text{opposite}}{\text{adjacent}}\), and \(\sec\theta=\frac{\text{hypotenuse}}{\text{adjacent}}\). Here, the side of length \(4\) is opposite the \(24^{\circ}\) angle and \(x\) is the hypotenuse. So we use the sine function since \(\sin(24^{\circ})=\frac{4}{x}\).

Answer:

Sine