Question

what is the order of rotational symmetry for a rhombus?
1
2
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4

Explanation:

Step1: Recall the definition of rotational symmetry order

The order of rotational symmetry of a shape is the number of times it can be rotated around a full \(360^{\circ}\) rotation so that it looks the same as the original shape.

Step2: Analyze the rhombus

A rhombus looks the same when rotated by \(180^{\circ}\) (half - turn). If we rotate it by \(90^{\circ}\), it does not match the original shape (unless it is a square, but a general rhombus is not a square). When we rotate it by \(360^{\circ}\div2 = 180^{\circ}\), it coincides with the original shape. And when we rotate it \(360^{\circ}\) (a full - turn), it also coincides with the original shape. The number of non - negative angles of rotation (\(\theta\), \(0^{\circ}<\theta\leq360^{\circ}\)) for which the shape coincides with the original is \(2\) (i.e., \(\theta = 180^{\circ}\) and \(\theta=360^{\circ}\)).

Answer:

2