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in parallelogram wxyz, diagonals \\(\overline{wy}\\) and \\(\overline{xz}\\) intersect at a. \\(wa = x^2 - 24\\) and \\(ay = 2x\\).
what is wy?
enter your answer in the box.
\\(wy = \square\\) units
Step1: Set WA = AY
In a parallelogram, diagonals bisect each other, so $WA = AY$.
$x^2 - 24 = 2x$
Step2: Solve quadratic equation
Rearrange: $x^2 - 2x - 24 = 0$.
Factor: $(x - 6)(x + 4) = 0$.
Solutions: $x = 6$ or $x = -4$. Length can't be negative, so $x = 6$.
Step3: Calculate WY
$WY = WA + AY = 2 \times AY = 2 \times (2x) = 4x$.
Substitute $x = 6$: $WY = 4 \times 6 = 24$.
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