Question

use the two points on the line to find its slope. m = -? remember: slope = rise/run

Explanation:

Step1: Identify two points

From the graph, the two points are \((0, 2)\) and \((3, 1)\).

Step2: Calculate rise and run

Rise is the change in \(y\)-values: \(1 - 2=-1\). Run is the change in \(x\)-values: \(3 - 0 = 3\).

Step3: Compute slope

Slope \(m=\frac{\text{rise}}{\text{run}}=\frac{-1}{3}=-\frac{1}{3}\). So the numerator (the "?") is \(1\) and the denominator is \(3\). But since the question shows \(m = -\frac{?}{?}\), and we found rise is \(-1\) (or we can take absolute values for the fraction's numerator and denominator as the negative sign is already factored out), the numerator "?" is \(1\) and denominator is \(3\). But looking at the graph's right triangle, the vertical change (rise) is \(1\) (downward, so negative, but the fraction's numerator in the given form \(m = -\frac{?}{?}\) would be the absolute value of the rise, and run is \(3\). So the "?" is \(1\) over \(3\), but the question's box is for the numerator? Wait, the graph shows a right triangle with vertical leg 1 (down) and horizontal leg 3 (right). So rise is \(-1\), run is \(3\), so slope is \(\frac{-1}{3}=-\frac{1}{3}\). So the numerator (the "?") is \(1\), denominator is \(3\). But the question's first box is the numerator, second is denominator. But the problem says "m = - [?]/[?]", so the numerator is \(1\), denominator is \(3\). Wait, let's check again. The two points: when moving from \((0,2)\) to \((3,1)\), we go down 1 (rise = -1) and right 3 (run = 3). So slope is \(\frac{-1}{3}=-\frac{1}{3}\). So the "?" in the numerator is \(1\), denominator is \(3\).

Answer:

The numerator (the "?") is \(1\) and denominator is \(3\). But since the question is asking for the "?" in \(m = -\frac{?}{?}\), the value of "?" (the numerator) is \(1\) (and denominator is \(3\)). But if we consider the fraction as \(\frac{1}{3}\) with the negative sign outside, then the "?" is \(1\).