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use the rectangle. round to the nearest tenth. the perimeter of the rec…

Question

use the rectangle. round to the nearest tenth.
the perimeter of the rectangle is units.
the area of the rectangle is square units.

Explanation:

Step1: Find the coordinates of the points

Assume \(A=(2,4)\), \(B=(3,1)\), \(C=(8,3)\), \(D=(7,6)\)

Step2: Calculate the length of \(AB\) using the distance formula \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)

For \(A=(2,4)\) and \(B=(3,1)\):
\(AB=\sqrt{(3 - 2)^2+(1 - 4)^2}=\sqrt{1 + 9}=\sqrt{10}\approx3.2\)

Step3: Calculate the length of \(BC\)

For \(B=(3,1)\) and \(C=(8,3)\):
\(BC=\sqrt{(8 - 3)^2+(3 - 1)^2}=\sqrt{25+4}=\sqrt{29}\approx5.4\)

Step4: Calculate the perimeter \(P\) of the rectangle (\(P = 2(l + w)\))

\(P=2(AB + BC)=2(\sqrt{10}+\sqrt{29})\approx2(3.2 + 5.4)=17.2\)

Step5: Calculate the area \(A\) of the rectangle (\(A=l\times w\))

\(A=\sqrt{10}\times\sqrt{29}=\sqrt{290}\approx17.0\)

Answer:

The perimeter of the rectangle is \(17.2\) units. The area of the rectangle is \(17.0\) square units.