QUESTION IMAGE
Question
use the information given in the diagram to find the measure of the missing angles.
Step1: Identify right angle
The diagram has a right angle (marked by the square), so that angle is \( 90^\circ \). The given angle is \( 68^\circ \). For the angle adjacent to \( 68^\circ \) and the right angle, we use the fact that a straight line is \( 180^\circ \), but first, let's find the angle between the vertical (right angle) and the horizontal. Wait, actually, the right angle, \( 68^\circ \), and the first missing angle (top left) sum to \( 180^\circ \)? No, wait, the right angle is \( 90^\circ \), so the angle between the top arrow and the left - right horizontal line: the angle next to \( 68^\circ \) (the one with the square) is \( 90^\circ \), so the angle above the left - right line (let's call it \( \angle1 \)): \( \angle1 + 90^\circ+ 68^\circ= 180^\circ \)? No, wait, the left - right line is a straight line (\( 180^\circ \)). The right angle is \( 90^\circ \), the \( 68^\circ \) angle, and \( \angle1 \) (the angle above the left - right line, between the top arrow and the left - right line) should satisfy \( \angle1+ 90^\circ + 68^\circ= 180^\circ \)? Wait, no, that's not right. Wait, the right angle is between the top arrow and the line going down - right? No, looking at the diagram, the left - right line is a straight line. The right angle is between the top arrow and the line going down - right? Wait, maybe better to see: the angle with the square is \( 90^\circ \), the given angle is \( 68^\circ \), so the angle between the top arrow and the right - hand horizontal line: let's call the top - left missing angle \( A \), the bottom - left missing angle \( B \), and the bottom - right missing angle \( C \).
First, the angle between the top arrow and the left - right horizontal line (angle \( A \)): since the right angle is \( 90^\circ \) and the given angle is \( 68^\circ \), and these three angles (\( A \), \( 90^\circ \), \( 68^\circ \)) are on a straight line (sum to \( 180^\circ \)), so \( A=180 - 90 - 68=22^\circ \)? Wait, no, that can't be. Wait, no, the right angle is \( 90^\circ \), the \( 68^\circ \) angle, and angle \( A \) (the angle above the left - right line, between the top arrow and the left - right line) – actually, the right angle is between the top arrow and the line going down to the right. So the top arrow, the right - angle line, and the right - hand horizontal line: the angle between top arrow and right - hand horizontal line is \( 90^\circ+ 68^\circ \)? No, I think I messed up. Wait, the left - right line is a straight line (\( 180^\circ \)). The angle with the square is \( 90^\circ \), the given angle is \( 68^\circ \), so the angle between the top arrow and the left - hand side of the horizontal line (angle \( A \)): \( A = 180-(90 + 68)=22^\circ \)? Wait, no, that's not. Wait, maybe the right angle is \( 90^\circ \), so the angle between the top arrow and the right - hand horizontal line is \( 90^\circ \), and the \( 68^\circ \) angle is adjacent to it. Wait, no, the diagram has a right angle (90 degrees), a 68 - degree angle, and then we have vertical angles or supplementary angles.
Wait, let's start over. The left - right line is a straight angle (\( 180^\circ \)). The angle with the square is \( 90^\circ \), the given angle is \( 68^\circ \), so the angle between the top arrow and the left - right line (let's call it angle \( X \)): \( X+90^\circ + 68^\circ=180^\circ \)? No, that would mean \( X = 180 - 90 - 68 = 22^\circ \). Then, the angle below the left - right line (angle \( B \)): since it's a straight line, angle \( B = 180^\circ \) (no, wait, no, the bottom - left angle is a s…
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Top - left angle: \( 22^\circ \), Bottom - left angle: \( 180^\circ \), Bottom - right angle: \( 22^\circ \), Right - angle: \( 90^\circ \) (but the right - angle is already marked, the missing angles are \( 22^\circ \), \( 180^\circ \), \( 22^\circ \))