QUESTION IMAGE
Question
use efficient methods find ( mangle abc ).
Step1: Use the triangle congruence
Since \(AD = DC\) and \(AC = CB\) (marked as equal), and \(\angle ADC = 92^{\circ}\). First, find \(\angle ACD\). In \(\triangle ADC\), \(\angle DAC=\angle DCA\) (isosceles triangle property). Let \(\angle DAC = \angle DCA=x\). Then \(x + x+92^{\circ}=180^{\circ}\) (sum of angles in a triangle). So \(2x=180^{\circ}-92^{\circ}=88^{\circ}\), \(x = 44^{\circ}\). Then \(\angle ACB = 180^{\circ}-\angle ACD=180^{\circ}- 44^{\circ}=136^{\circ}\).
Step2: Use the isosceles triangle property again
In \(\triangle ACB\), \(AC = CB\), so \(\angle CAB=\angle CBA\). Let \(\angle CAB=\angle CBA = y\). Then \(y + y+136^{\circ}=180^{\circ}\) (sum of angles in a triangle). \(2y=180^{\circ}-136^{\circ}=44^{\circ}\), \(y = 22^{\circ}\).
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