Question

use the dimensions of the refrigerator shown below for your work. if the refrigerator is advertised as a 19 - cu - ft refrigerator, how much space is taken up by the motor, insulation, and so on? ft³ 33 in. 36 in. 66 in. resources read it

Explanation:

Step1: Calculate the volume of the refrigerator in cubic inches

The volume \(V\) of a rectangular prism (refrigerator) is given by \(V = l\times w\times h\). Here, \(l = 36\) in, \(w=33\) in, \(h = 66\) in.

$$V=36\times33\times66$$

$$V = 36\times(33\times66)=36\times2178 = 78408\space\text{in}^3$$

Step2: Convert the volume from cubic inches to cubic feet

Since \(1\space\text{ft}=12\space\text{in}\), \(1\space\text{ft}^3=(12)^3 = 1728\space\text{in}^3\).
Let \(x\) be the volume in cubic feet. Then \(x=\frac{78408}{1728}\)

$$x=\frac{78408\div12}{1728\div12}=\frac{6534}{144}$$

$$x=\frac{6534\div6}{144\div6}=\frac{1089}{24}= 45.375\space\text{ft}^3$$

Step3: Find the space taken up by non - storage components

The advertised storage space is \(19\space\text{ft}^3\).
The space taken up by motor, insulation etc. \(y=45.375 - 19\)

$$y = 26.375\space\text{ft}^3$$

Answer:

\(26.375\)