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Question
use the diagram to complete the statement. given △jkl, sin(38°) equals cos(38°). cos(52°). tan(38°). tan(52°).
Step1: Recall the co - function identity
The co - function identity states that \(\sin\theta=\cos(90^{\circ}-\theta)\).
Step2: Apply the identity
If \(\theta = 38^{\circ}\), then \(90^{\circ}-\theta=90^{\circ}-38^{\circ} = 52^{\circ}\). So, \(\sin(38^{\circ})=\cos(52^{\circ})\).
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\(\cos(52^{\circ})\)