Question

trigonometric ratios in right triang... find \\( \sin ( \alpha ) \\) in the triangle. draw on exercise

Explanation:

Step1: Recall the definition of sine in a right - triangle

In a right - triangle, \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\). For angle \(\alpha\), the side opposite to \(\alpha\) is \(BC = 12\), and the hypotenuse is \(AB=37\).

Answer:

\(\sin(\alpha)=\frac{12}{37}\)