Question

1. triangle fgh with vertices f(-7,8), g(-1,1), and h(-8,4): 270° counterclockwise

4
f (_,_)
g (_,_)
h (_,_)

Explanation:

Step1: Recall the rotation rule

The rule for a \(270^{\circ}\) counter - clockwise rotation about the origin \((x,y)\to(y, - x)\).

Step2: Apply the rule to point \(F(-7,8)\)

For \(F(-7,8)\), using the rule \((x,y)\to(y, - x)\), we substitute \(x=-7\) and \(y = 8\). So \(F'=(8,7)\).

Step3: Apply the rule to point \(G(-1,1)\)

For \(G(-1,1)\), substitute \(x=-1\) and \(y = 1\) into the rule \((x,y)\to(y, - x)\). Then \(G'=(1,1)\).

Step4: Apply the rule to point \(H(-8,4)\)

For \(H(-8,4)\), substitute \(x=-8\) and \(y = 4\) into the rule \((x,y)\to(y, - x)\). So \(H'=(4,8)\).

Answer:

\(F'(8,7)\), \(G'(1,1)\), \(H'(4,8)\)