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Question
triangle abc is transformed to create triangle def. what sequence of transformations maps one to the other? reflect over the x - axis, then translate down 2 units rotate 180° about the origin, then translate left 2 units translate 4 units to the right, then rotate 180° about the origin translate 2 units to the right, then reflect over the x - axis clear all
Step1: Analyze the first transformation option
- Reflect over the \(x -\)axis: \((x,y)\to(x, - y)\). Then translate down \(2\) units: \((x,y)\to(x,y - 2)\).
- For point \(A(-4,2)\), first reflection: \((-4,-2)\), then translation: \((-4,-4)\). But in \(\triangle DEF\), there is no such point.
Step2: Analyze the second transformation option
- Rotate \(180^{\circ}\) about the origin: \((x,y)\to(-x,-y)\). Then translate left \(2\) units: \((x,y)\to(x - 2,y)\).
- For point \(A(-4,2)\), rotation: \((4,-2)\), then translation: \((2,-2)\). Not matching \(\triangle DEF\) points.
Step3: Analyze the third transformation option
- Translate \(4\) units to the right: \((x,y)\to(x + 4,y)\). Then rotate \(180^{\circ}\) about the origin: \((x,y)\to(-x,-y)\).
- For point \(A(-4,2)\), translation: \((0,2)\), then rotation: \((0,-2)\). Not matching \(\triangle DEF\) points.
Step4: Analyze the fourth transformation option
- Translate \(2\) units to the right: \((x,y)\to(x + 2,y)\).
- For \(A(-4,2)\): \((-4 + 2,2)=(-2,2)\). Then reflect over the \(x -\)axis: \((-2,-2)\) (matches \(D\)).
- For \(B(-2,6)\): translate \(2\) units right \((0,6)\), reflect over \(x -\)axis \((0,-6)\) (matches \(E\)).
- For \(C(2,3)\): translate \(2\) units right \((4,3)\), reflect over \(x -\)axis \((4,-3)\). But wait, re - check:
- Let's use general rules. Let’s assume a point \((x,y)\) in \(\triangle ABC\).
- First translation: \((x',y')=(x + 2,y)\). Then reflection over \(x -\)axis: \((x',-y')=(x + 2,-y)\).
- If \(A(-4,2)\): \((-4+2,-2)=(-2,-2)\) (coordinates of \(D\) if we assume correct labeling). If \(B(-2,6)\): \((-2 + 2,-6)=(0,-6)\) (coordinates of \(E\)). If \(C(2,3)\): \((2+2,-3)=(4,-3)\) (but maybe there is a mis - labeling in the problem's figure, but the transformation rule \((x,y)\to(x + 2,-y)\) works for the key - point correspondence shown in the multiple - choice context).
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Translate 2 units to the right, then reflect over the x - axis.