QUESTION IMAGE
Question
- a translation has the rule (x,y)→(x + 3,y - 3). find the image of x(2,5). find the preimage of y(4,4). 4. a triangle has vertices a(7,11), b(-5,1), and c(4,-2). after a translation, it is known that a(8,10). write a rule for the translation: find the coordinates for b and c:
3.
Find the image of \(X(2,5)\)
Step1: Apply \(x\) - coordinate rule
For the \(x\) - coordinate of the image, use the rule \(x
ightarrow x + 3\). Given \(x = 2\), then \(x'=2 + 3=5\).
Step2: Apply \(y\) - coordinate rule
For the \(y\) - coordinate of the image, use the rule \(y
ightarrow y - 3\). Given \(y = 5\), then \(y'=5 - 3 = 2\).
Step1: Set up equations for pre - image
Let the pre - image be \((x,y)\). The translation rule is \((x,y)
ightarrow(x + 3,y - 3)\). So we have the equations \(x+3 = 4\) and \(y - 3=4\).
Step2: Solve for \(x\)
Solve \(x+3 = 4\) for \(x\). Subtract 3 from both sides: \(x=4 - 3=1\).
Step3: Solve for \(y\)
Solve \(y - 3=4\) for \(y\). Add 3 to both sides: \(y=4 + 3 = 7\).
Step1: Find the change in \(x\) - coordinate
Given \(A(7,11)\) and \(A'(8,10)\). The change in the \(x\) - coordinate is \(\Delta x=8 - 7=1\).
Step2: Find the change in \(y\) - coordinate
The change in the \(y\) - coordinate is \(\Delta y=10 - 11=-1\).
The translation rule is \((x,y)
ightarrow(x + 1,y - 1)\).
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\((5,2)\)