Question

suppose that you must order concrete for a sidewalk that is to be 59 ft by 6 ft to a depth of 3 in. how much concrete is required? (answer to the nearest \\( \frac { 1 } { 2 } \\) cubic yard )

Explanation:

Step1: Convert all units to yards

Since \(1\) yard \( = 3\) feet and \(1\) yard \(= 36\) inches.
Length \(l = 59\) ft \(=\frac{59}{3}\) yd, width \(w = 6\) ft \(=\frac{6}{3}=2\) yd, depth \(h = 3\) in \(=\frac{3}{36}=\frac{1}{12}\) yd.

Step2: Calculate the volume

The volume \(V\) of a rectangular - prism (which the sidewalk is modeled as) is \(V=l\times w\times h\).
Substitute the values: \(V=\frac{59}{3}\times2\times\frac{1}{12}\).

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Rounding to the nearest \(\frac{1}{2}\) (i.e., \(0.5\)), \(3.28\approx 3.5\)

Answer:

\(3.5\)