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Question
suppose m is the midpoint of \\(\overline{fg}\\). find the missing measure. \\(fm = 5y + 13\\), \\(mg = 5 - 3y\\) \\(fg = \boxed{}\\) need help?
Step1: Use midpoint property
Since \( M \) is the midpoint of \( \overline{FG} \), \( FM = MG \). So set \( 5y + 13 = 5 - 3y \).
Step2: Solve for \( y \)
\( 5y + 3y = 5 - 13 \)
\( 8y = -8 \)
\( y = -1 \).
Step3: Find \( FM \) and \( MG \)
Substitute \( y = -1 \) into \( FM \): \( 5(-1) + 13 = -5 + 13 = 8 \).
\( MG \) is also \( 8 \) (since \( FM = MG \)).
Step4: Calculate \( FG \)
\( FG = FM + MG = 8 + 8 = 16 \).
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\( 16 \)