QUESTION IMAGE
Question
statements
- \\( \overleftrightarrow { c m } \\) is a perpendicular bisector of \\( \overline { a b } \\) at point
m.
- \\( \overleftrightarrow { c m } \perp \overline { a b } \\)
- \\( \angle a m c \\) and \\( \angle b m c \\) are right \\( \angle \\) s.
4.
- \\( m \\) is the midpoint of \\( \overline { a b } \\)
- \\( \overline { a m } \cong \overline { m b } \\)
7.
- \\( \triangle a m c \cong \triangle b m c \\)
- \\( \overline { a c } \cong \overline { b c } \\)
- \\( a c = b c \\)
a. \\( \perp \\) bisector
b. \\( \angle a m c \cong \angle b m c \\)
c. midpoint
d. \\( \overline { c m } \cong \overline { c m } \\)
e. def. of \\( \perp \\)
f. \\( c m = c m \\)
g. cpctc
h. \\( \angle a m c \cong \angle a m c \\)
Step1: Reason for statement 2
Since \( \overleftrightarrow{CM}\) is a perpendicular bisector (given), by the definition of perpendicular (\( \perp\)), \( \overleftrightarrow{CM}\perp\overline{AB}\). So the reason for statement 2 is "Def. of \( \perp\)" (option e).
Step2: Reason for statement 3
If two lines are perpendicular, the angles formed are right angles. By the definition of perpendicular lines (\( \overleftrightarrow{CM}\perp\overline{AB}\)), \( \angle AMC\) and \( \angle BMC\) are right angles. The reason is based on the "Def. of \( \perp\)" (related to the formation of right - angles from perpendicular lines).
Step3: Statement 4
Since \( \angle AMC\) and \( \angle BMC\) are right angles and we use the Right \( \angle\) Congruence Theorem (which states that all right angles are congruent), the statement is \( \angle AMC\cong\angle BMC\) (option b).
Step4: Reason for statement 6
Since \(M\) is the mid - point of \( \overline{AB}\) (statement 5, by the definition of a mid - point (\(M\) divides \( \overline{AB}\) into two equal parts), \( \overline{AM}\cong\overline{MB}\). The reason is "Def. of Midpoint" (option c).
Step5: Statement 7
By the Reflexive Property of Congruence (\( \cong\)), any segment is congruent to itself. So \( \overline{CM}\cong\overline{CM}\) (option d).
Step6: Reason for statement 9
Since \( \triangle AMC\cong\triangle BMC\) (statement 8) by \(SAS\) ( \( \overline{AM}\cong\overline{MB}\), \( \angle AMC\cong\angle BMC\), \( \overline{CM}\cong\overline{CM}\)), then by CPCTC (Corresponding Parts of Congruent Triangles are Congruent), \( \overline{AC}\cong\overline{BC}\). The reason is "CPCTC" (option g).
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- e. Def. of \( \perp\)
- e. Def. of \( \perp\)
- b. \( \angle AMC\cong\angle BMC\)
- c. Midpoint
- d. \( \overline{CM}\cong\overline{CM}\)
- g. CPCTC