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a 4 m by 4 m square is cut out of a right triangle whose base is 16 m l…

Question

a 4 m by 4 m square is cut out of a right triangle whose base is 16 m long and whose height is 9.5 m. what is the area of the part of the triangle that remains? 60 meters squared -16 meters squared 16 meters squared 76 meters squared

Explanation:

Step1: Calculate the area of the triangle

The formula for the area of a triangle is \(A=\frac{1}{2}\times base\times height\).
Given \(base = 16m\) and \(height=9.5m\), then \(A_{triangle}=\frac{1}{2}\times16\times9.5\).

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Step2: Calculate the area of the square

The formula for the area of a square is \(A = side\times side\).
Given \(side = 4m\), then \(A_{square}=4\times4=16m^{2}\)

Step3: Calculate the remaining area

The remaining area \(A = A_{triangle}-A_{square}\)

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Answer:

60 meters squared