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Question
sp# 9 9. if △gfe ~ △ghj, find the value of x.
Step1: Use the property of similar triangles
Since \(\triangle GFE\sim\triangle GHJ\), the ratios of corresponding sides are equal. So, \(\frac{EF}{HJ}=\frac{EG}{HG}\).
Step2: Substitute the given values
We have \(EF = x + 6\), \(HJ=7.5\), \(EG = 12\), and \(HG=2x + 1\). Then \(\frac{x + 6}{7.5}=\frac{12}{2x + 1}\).
Step3: Cross - multiply
Cross - multiplying gives \((x + 6)(2x + 1)=12\times7.5\).
Expand the left - hand side: \(2x^{2}+x+12x + 6=90\).
Simplify to get \(2x^{2}+13x+6 - 90=0\), i.e., \(2x^{2}+13x - 84=0\).
Step4: Solve the quadratic equation
For a quadratic equation \(ax^{2}+bx + c = 0\) (\(a = 2\), \(b = 13\), \(c=-84\)), we can use the quadratic formula \(x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}\).
First, calculate the discriminant \(\Delta=b^{2}-4ac=(13)^{2}-4\times2\times(-84)=169 + 672=841\).
Then \(x=\frac{-13\pm\sqrt{841}}{4}=\frac{-13\pm29}{4}\).
We have two solutions: \(x_{1}=\frac{-13 + 29}{4}=\frac{16}{4}=4\) and \(x_{2}=\frac{-13-29}{4}=\frac{-42}{4}=-10.5\).
Since length cannot be negative, we reject \(x=-10.5\).
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\(x = 4\)