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QUESTION IMAGE

solve for x. round to the nearest tenth of a degree, if necessary. answ…

Question

solve for x. round to the nearest tenth of a degree, if necessary.
answer attempt 2 out of 2
x =
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Explanation:

Step1: Identify the trigonometric ratio

In a right - triangle \( \triangle VWU\) with right - angle at \(V\), we know the opposite side (\(VU = 4.4\)) and the hypotenuse (\(WU=7.1\)). The sine ratio is defined as \(\sin\theta=\frac{\text{opposite}}{\text{hypotenuse}}\). So, \(\sin x=\frac{4.4}{7.1}\).

Step2: Solve for \(x\)

Take the inverse - sine (arcsin) of both sides. \(x = \sin^{-1}(\frac{4.4}{7.1})\).
Calculate \(\frac{4.4}{7.1}\approx0.6197\).
Then \(x=\sin^{-1}(0.6197)\). Using a calculator, \(x\approx38.3^{\circ}\).

Answer:

\(38.3\)